Answers Of A/L ICT Model Paper I 2017

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correction: answer for 4 (b):
no=0
sum=0
tot=[]
sub1=[give all the marks here]
sub2=[give all the marks here]
sub1=[give all the marks here]
while no<=len(index_no):
        sum=sub1[no]+ sub2[no]+ sub3[no] 
        tot.append(sum)
        print(index_no[no])+tot[no]
        sum=0
        no=no+1